| Name | pyiota JSON |
| Version |
1.2.1
JSON |
| download |
| home_page | |
| Summary | Simple Go lang iota pattern implementation |
| upload_time | 2023-03-24 18:31:44 |
| maintainer | @jedi2light |
| docs_url | None |
| author | @jedi2light |
| requires_python | >=3.6 |
| license | WTFPL |
| keywords |
|
| VCS |
|
| bugtrack_url |
|
| requirements |
No requirements were recorded.
|
| Travis-CI |
No Travis.
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| coveralls test coverage |
No coveralls.
|
# PyIota - Simple Go lang iota pattern implementation
## Simple Usage
```python3
from pyiota import iota
with iota.start():
A = iota()
B = iota()
C = iota()
with iota.start(10):
D = iota()
E = iota()
F = iota()
print(A, B, C, D, E, F) #=> '0 1 2 10 11 12'
```
## How it works?
0. Default `iota._counter` value equals to `-1`.
1. `A = iota()` - `iota.__new__()` increments `iota._counter` and returns it.
2. It is possible to reset `iota._counter` calling `iota()` within `with iota.start(): ...` block.
2.1. You can also provide a number to start from. For example: `D`, `E` and `F` from example above will be equal to `10`, `11`, and `12` accrordingly.
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"description": "# PyIota - Simple Go lang iota pattern implementation\n\n## Simple Usage\n\n```python3\nfrom pyiota import iota\n\nwith iota.start():\n A = iota()\n B = iota()\n C = iota()\nwith iota.start(10):\n D = iota()\n E = iota()\n F = iota()\nprint(A, B, C, D, E, F) #=> '0 1 2 10 11 12'\n```\n\n## How it works?\n\n0. Default `iota._counter` value equals to `-1`.\n1. `A = iota()` - `iota.__new__()` increments `iota._counter` and returns it.\n2. It is possible to reset `iota._counter` calling `iota()` within `with iota.start(): ...` block. \n 2.1. You can also provide a number to start from. For example: `D`, `E` and `F` from example above will be equal to `10`, `11`, and `12` accrordingly.\n",
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