ChemIITools


NameChemIITools JSON
Version 0.0.4 PyPI version JSON
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home_pagehttps://github.com/KGrewal1/ChemIITools
SummaryTools for Chemistry Part II programming
upload_time2023-01-04 21:41:37
maintainer
docs_urlNone
authorKGrewal1
requires_python>=3.7
licenseApache Software License 2.0
keywords nbdev jupyter notebook python
VCS
bugtrack_url
requirements No requirements were recorded.
Travis-CI No Travis.
coveralls test coverage No coveralls.
            ChemIITools
================

<!-- WARNING: THIS FILE WAS AUTOGENERATED! DO NOT EDIT! -->

Documentation can be found at https://kgrewal1.github.io/ChemIITools/

## Install

``` sh
pip install ChemIITools
```

## How to use

### Solve the Huckel Equation

Easily solve the Huckel equation for complex systems

``` python
mol = Huckel("c1cc2ccc3ccc4ccc5ccc6ccc1c7c2c3c4c5c67")
print(mol)
mol.molecule
```

    Huckel Energies (degeneracy) for c1cc2ccc3ccc4ccc5ccc6ccc1c7c2c3c4c5c67: [-2.675 (1)]  [-2.214 (2)]  [-1.675 (2)]  [-1.539 (1)]  [-1.214 (1)]  [-1.000 (3)]  [-0.539 (2)]  [0.539 (2)]  [1.000 (3)]  [1.214 (1)]  [1.539 (1)]  [1.675 (2)]  [2.214 (2)]  [2.675 (1)] 

![](index_files/figure-gfm/cell-3-output-2.svg)

``` python
mol.plot()
```

![](index_files/figure-gfm/cell-4-output-1.png)

### Parse .out files and plot energy surfaces

Plot potential energy surfaces of symmetric triatomics and find the
vibrational frequencies

``` python
surface_plot(h2o_vals)
```

![](index_files/figure-gfm/cell-6-output-1.png)

``` python
r_opt, theta_opt, nu_r, nu_theta = vib_calc(h2o_vals)
print('the optimum bond length of water is ', r_opt, ' angstroms with angle ', theta_opt, ' degrees' )
print('the stretching frequency ', round(nu_r), ' cm-1 and bending frequency ', round(nu_theta), ' cm-1' )
```

    the optimum bond length of water is  0.95  angstroms with angle  105.0  degrees
    the stretching frequency  3113  cm-1 and bending frequency  1665  cm-1

### Calculate steady state concentrations

Find the steady state concentration for chemical systems of the form
$$D  \xrightleftharpoons[k_{u}^{R15}]{k_{f}^{R15}}  I  \xrightleftharpoons[k_{u}^{R16}]{k_{f}^{R16}} N$$

``` python
kf1 = 26000
kr1 = 0.06
kf2 = 730
kr2 = 0.00075
urea_conc = np.linspace(0, 8, num=1000)
ss_conc = np.array([steady_state_calc(kf1*np.exp(-1.68*conc), kr1*np.exp(0.95*conc), kf2*np.exp(-1.72*conc), kr2*np.exp(1.20*conc)) for conc in urea_conc])
plt.plot(urea_conc,ss_conc[:, 0],label='D')
plt.plot(urea_conc,ss_conc[:, 1],label='I')
plt.plot(urea_conc,ss_conc[:, 2],label='N')
plt.xlabel('[Urea]/ M')
plt.ylabel('Fraction of Species')
plt.legend()
plt.show()
```

![](index_files/figure-gfm/cell-8-output-1.png)

### Caclualte time evolution of a chemical system

``` python
A, B, X, Y, Z, P, Q = 0.06, 0.06, 10**(-9.8),10**(-6.52), 10**(-7.32), 0, 0
concs = [A, B, X, Y, Z, P, Q]
t, conc_t= oreg_calc(concs)
As, Bs, Xs, Ys, Zs, Ps, Qs = conc_t
```

``` python
plt.plot(t[::10000],Xs[::10000],label='X')
plt.plot(t[::10000],Ys[::10000],label='Y')
plt.plot(t[::10000],Zs[::10000],label='Z')
plt.yscale('log')
plt.xlabel('time/ s')
plt.ylabel('Concentration/ M')
plt.legend(bbox_to_anchor =(1.15, 0.6))
plt.show()
```

![](index_files/figure-gfm/cell-10-output-1.png)

### Optimise Cluster Geometry

``` python
lj7 = System(7, '(4*((1/r)**12 -(1/r)**6))')
lj7.optimise()
print(lj7)
lj7.plot()
```

    Energy -16.505384, for 7 points

![](index_files/figure-gfm/cell-11-output-2.png)



            

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    "description": "ChemIITools\n================\n\n<!-- WARNING: THIS FILE WAS AUTOGENERATED! DO NOT EDIT! -->\n\nDocumentation can be found at https://kgrewal1.github.io/ChemIITools/\n\n## Install\n\n``` sh\npip install ChemIITools\n```\n\n## How to use\n\n### Solve the Huckel Equation\n\nEasily solve the Huckel equation for complex systems\n\n``` python\nmol = Huckel(\"c1cc2ccc3ccc4ccc5ccc6ccc1c7c2c3c4c5c67\")\nprint(mol)\nmol.molecule\n```\n\n    Huckel Energies (degeneracy) for c1cc2ccc3ccc4ccc5ccc6ccc1c7c2c3c4c5c67: [-2.675 (1)]  [-2.214 (2)]  [-1.675 (2)]  [-1.539 (1)]  [-1.214 (1)]  [-1.000 (3)]  [-0.539 (2)]  [0.539 (2)]  [1.000 (3)]  [1.214 (1)]  [1.539 (1)]  [1.675 (2)]  [2.214 (2)]  [2.675 (1)] \n\n![](index_files/figure-gfm/cell-3-output-2.svg)\n\n``` python\nmol.plot()\n```\n\n![](index_files/figure-gfm/cell-4-output-1.png)\n\n### Parse .out files and plot energy surfaces\n\nPlot potential energy surfaces of symmetric triatomics and find the\nvibrational frequencies\n\n``` python\nsurface_plot(h2o_vals)\n```\n\n![](index_files/figure-gfm/cell-6-output-1.png)\n\n``` python\nr_opt, theta_opt, nu_r, nu_theta = vib_calc(h2o_vals)\nprint('the optimum bond length of water is ', r_opt, ' angstroms with angle ', theta_opt, ' degrees' )\nprint('the stretching frequency ', round(nu_r), ' cm-1 and bending frequency ', round(nu_theta), ' cm-1' )\n```\n\n    the optimum bond length of water is  0.95  angstroms with angle  105.0  degrees\n    the stretching frequency  3113  cm-1 and bending frequency  1665  cm-1\n\n### Calculate steady state concentrations\n\nFind the steady state concentration for chemical systems of the form\n$$D  \\xrightleftharpoons[k_{u}^{R15}]{k_{f}^{R15}}  I  \\xrightleftharpoons[k_{u}^{R16}]{k_{f}^{R16}} N$$\n\n``` python\nkf1 = 26000\nkr1 = 0.06\nkf2 = 730\nkr2 = 0.00075\nurea_conc = np.linspace(0, 8, num=1000)\nss_conc = np.array([steady_state_calc(kf1*np.exp(-1.68*conc), kr1*np.exp(0.95*conc), kf2*np.exp(-1.72*conc), kr2*np.exp(1.20*conc)) for conc in urea_conc])\nplt.plot(urea_conc,ss_conc[:, 0],label='D')\nplt.plot(urea_conc,ss_conc[:, 1],label='I')\nplt.plot(urea_conc,ss_conc[:, 2],label='N')\nplt.xlabel('[Urea]/ M')\nplt.ylabel('Fraction of Species')\nplt.legend()\nplt.show()\n```\n\n![](index_files/figure-gfm/cell-8-output-1.png)\n\n### Caclualte time evolution of a chemical system\n\n``` python\nA, B, X, Y, Z, P, Q = 0.06, 0.06, 10**(-9.8),10**(-6.52), 10**(-7.32), 0, 0\nconcs = [A, B, X, Y, Z, P, Q]\nt, conc_t= oreg_calc(concs)\nAs, Bs, Xs, Ys, Zs, Ps, Qs = conc_t\n```\n\n``` python\nplt.plot(t[::10000],Xs[::10000],label='X')\nplt.plot(t[::10000],Ys[::10000],label='Y')\nplt.plot(t[::10000],Zs[::10000],label='Z')\nplt.yscale('log')\nplt.xlabel('time/ s')\nplt.ylabel('Concentration/ M')\nplt.legend(bbox_to_anchor =(1.15, 0.6))\nplt.show()\n```\n\n![](index_files/figure-gfm/cell-10-output-1.png)\n\n### Optimise Cluster Geometry\n\n``` python\nlj7 = System(7, '(4*((1/r)**12 -(1/r)**6))')\nlj7.optimise()\nprint(lj7)\nlj7.plot()\n```\n\n    Energy -16.505384, for 7 points\n\n![](index_files/figure-gfm/cell-11-output-2.png)\n\n\n",
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